Polansky P.CAN () vs Muller A.FRA ()
predictions and statistics
16/01/2020 01:10
Australian Open, surface: Hard
| Round | Match | Prob. in % | Tip | Games | FT | |
|---|---|---|---|---|---|---|
| QR128 |
Polansky P.(CAN) Muller A.(FRA) 16/01/2020 01:10
|
1
2
6
6
|
0 2
|
|||
All matches between both players
Polansky P.
0
0%
Muller A.
3
100%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
Australian OpenAustralia.. QR64 |
12/01/2021 |
Polansky P. Muller A. 12/01/2021
|
0
1
6
6
|
0 2
|
|
Australian OpenAustralia.. QR128 |
16/01/2020 |
Polansky P. Muller A. 16/01/2020
|
1
2
6
6
|
0 2
|
|
Roland GarrosRoland Ga.. QR64 |
22/05/2019 |
Polansky P. Muller A. 22/05/2019
|
2
6
6
6
4
7
|
1 2
|
Polansky P. performance on Hard
Win
23
33%
Lose
44
64%
Total matches: 69
Cancelled: 2
Muller A. performance on Hard
Win
26
45%
Lose
29
50%
Total matches: 58
Cancelled: 3
Last 6 matches Polansky P.
Win
0
0%
Lose
6
100%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Toronto MastersToronto M.. QR32 |
Purcell M. Polansky P. 05/08/2023
|
6
6
2
4
|
2 0
|
|
WashingtonWashington QR32 |
Polansky P. Kwiatkowski T. 29/07/2023
|
2
0
6
6
|
0 2
|
|
NewportNewport QR16 |
Mansouri S. Polansky P. 16/07/2023
|
6
7
2
5
|
2 0
|
|
Indian WellsIndian We.. QR64 |
Van De Zandschulp B. Polansky P. 06/10/2021
|
6
6
3
3
|
2 0
|
|
US OpenUS Open QR128 |
Dzumhur D. Polansky P. 25/08/2021
|
4
7
6
6
6
0
|
2 1
|
|
Toronto MastersToronto M.. QR16 |
Polansky P. Duckworth J. 08/08/2021
|
6
1
2
4
6
6
|
1 2
|
Last 6 matches Muller A.
Win
2
33%
Lose
4
67%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
BarcelonaBarcelona R32 |
Muller A. Ruud C. 17/04/2024
|
3
4
6
6
|
0 2
|
|
BarcelonaBarcelona R64 |
Muller A. Ramos A. 15/04/2024
|
7
6
6
0
|
2 0
|
|
Monte CarloMonte Car.. QR16 |
Muller A. Nardi L. 07/04/2024
|
6
4
4
3
6
6
|
1 2
|
|
Monte CarloMonte Car.. QR32 |
Lajovic D. Muller A. 06/04/2024
|
2
3
6
6
|
0 2
|
|
MarrakechMarrakech R32 |
Vukic A. Muller A. 02/04/2024
|
6
7
3
6
|
2 0
|
|
MiamiMiami R128 |
Muller A. Kwon S. 21/03/2024
|
6
3
7
6
|
0 2
|