Zverev A.GER (285) vs Kamke T.GER (83)
predictions and statistics
14/07/2014 00:00
Hamburg, surface: Clay
| Round | Match | Prob. in % | Tip | Games | FT | |
|---|---|---|---|---|---|---|
| QF |
Zverev A.(GER) Kamke T.(GER) 14/07/2014 00:00
|
0
7
6
6
5
3
|
2 1
|
|||
All matches between both players
Zverev A.
2
100%
Kamke T.
0
0%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
StockholmStockholm QF |
21/10/2016 |
Zverev A. Kamke T. 21/10/2016
|
6
7
3
6
|
2 0
|
|
HamburgHamburg QF |
14/07/2014 |
Zverev A. Kamke T. 14/07/2014
|
0
7
6
6
5
3
|
2 1
|
Zverev A. performance on Clay
Win
179
70%
Lose
67
26%
Total matches: 256
Cancelled: 10
Kamke T. performance on Clay
Win
25
46%
Lose
29
54%
Total matches: 54
Cancelled: 0
Last 6 matches Zverev A.
Win
4
67%
Lose
2
33%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
StuttgartStuttgart ATP Stuttgart - Final |
Zverev A. Fritz T. 15/06/2025
|
3
6
6
7
|
0 2
|
|
StuttgartStuttgart ATP Stuttgart - Semi-finals |
Zverev A. Shelton B. 14/06/2025
|
7
8
7
6
|
2 0
|
|
StuttgartStuttgart ATP Stuttgart - Quarter-finals |
Zverev A. Nakashima B. 13/06/2025
|
7
6
5
4
|
2 0
|
|
StuttgartStuttgart ATP Stuttgart - 1/8-finals |
Zverev A. Moutet C. 12/06/2025
|
6
8
2
7
|
2 0
|
|
Roland GarrosRoland Ga.. ATP French Open - Quarter-finals |
Zverev A. Djokovic N. 04/06/2025
|
6
3
2
4
4
6
6
6
|
1 3
|
|
Roland GarrosRoland Ga.. ATP French Open - 1/8-finals |
Zverev A. Griekspoor T. 02/06/2025
|
6
3
4
0
|
Ret |
Last 6 matches Kamke T.
Win
2
33%
Lose
4
67%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Australian OpenAustralia.. QR32 |
Marterer M. Kamke T. 14/01/2022
|
6
6
4
1
|
2 0
|
|
Australian OpenAustralia.. QR64 |
Kuzmanov D. Kamke T. 12/01/2022
|
5
4
7
6
|
0 2
|
|
Australian OpenAustralia.. QR128 |
Kamke T. Gaio F. 11/01/2022
|
6
6
4
2
|
2 0
|
|
US OpenUS Open QR128 |
Kamke T. Marchenko I. 24/08/2021
|
6
6
2
3
7
6
|
1 2
|
|
HamburgHamburg QR32 |
Kamke T. Giannessi A. 10/07/2021
|
3
4
6
6
|
0 2
|
|
WimbledonWimbledon QR128 |
Seyboth Wild T. Kamke T. 22/06/2021
|
6
6
4
4
|
2 0
|