Azarenka V.BLR (27) vs Torro Flor M.ESP (131)
predictions and statistics

25/05/2015 00:00
Roland Garros, surface: Clay
Round | Match | Prob. in % | Tip | Games | FT | |
---|---|---|---|---|---|---|
R128 |
Azarenka V.(BLR) Torro Flor M.(ESP) 25/05/2015 00:00
|
6
6
2
1
|
2 0
|
All matches between both players
Azarenka V.
1
100%
Torro Flor M.
0
0%
TournamentTour. | Date | Match | Games | FT |
---|---|---|---|---|
Roland GarrosRoland Ga.. R128 |
25/05/2015 |
Azarenka V. Torro Flor M. 25/05/2015
|
6
6
2
1
|
2 0
|
Azarenka V. performance on Clay
Win
119
64%
Lose
55
29%
Total matches: 187
Cancelled: 10
Torro Flor M. performance on Clay
Win
18
42%
Lose
25
58%
Total matches: 43
Cancelled: 0
Last 6 matches Azarenka V.
Win
3
50%
Lose
3
50%
Tour. | Match | Games | FT |
---|---|---|---|
WimbledonWimbledon WTA Wimbledon - 1/64-finals |
Azarenka V. Zakharova A. 01/07/2025
|
2
6
1
6
2
6
|
1 2
|
Bad HomburgBad Hombu.. WTA Bad Homburg - 1/8-finals |
Azarenka V. Swiatek I. 24/06/2025
|
4
4
6
6
|
0 2
|
Bad HomburgBad Hombu.. WTA Bad Homburg - 1/16-finals |
Azarenka V. Siegemund L. 23/06/2025
|
6
6
2
2
|
2 0
|
Bad HomburgBad Hombu.. WTA Bad Homburg - Final - Qualification |
Kudermetova V. Azarenka V. 22/06/2025
|
8
3
4
6
6
6
|
1 2
|
Roland GarrosRoland Ga.. WTA French Open - 1/32-finals |
Azarenka V. Kenin S. 29/05/2025
|
7
4
8
6
|
0 2
|
Roland GarrosRoland Ga.. WTA French Open - 1/64-finals |
Wickmayer Y. Azarenka V. 27/05/2025
|
0
0
6
6
|
0 2
|
Last 6 matches Torro Flor M.
Win
2
33%
Lose
4
67%
Tour. | Match | Games | FT |
---|---|---|---|
Australian OpenAustralia.. QR96 |
Torro Flor M. Kuzmova V. 11/01/2018
|
4
4
6
6
|
0 2
|
BucharestBucharest R32 |
Eguchi M. Torro Flor M. 12/07/2016
|
6
6
1
2
|
2 0
|
Rio OpenRio Open R32 |
Torro Flor M. Erakovic M. 16/02/2016
|
6
7
2
7
6
6
|
1 2
|
Australian OpenAustralia.. QR96 |
Kania P. Torro Flor M. 14/01/2016
|
2
6
6
6
4
2
|
2 1
|
FlorianopolisFlorianop.. R16 |
Torro Flor M. Maria T. 27/07/2015
|
6
6
3
1
|
2 0
|
FlorianopolisFlorianop.. R32 |
Torro Flor M. Peterson R. 27/07/2015
|
6
7
3
5
|
2 0
|