Danilovic O.SRB () vs Niemeier J.GER ()
predictions and statistics
23/04/2024 12:40
Madrid, surface: Clay
| Round | Match | Prob. in % | Tip | Games | FT | |
|---|---|---|---|---|---|---|
| QR32 |
Danilovic O.(SRB) Niemeier J.(GER) 23/04/2024 12:40
|
6
6
4
4
|
2 0
|
|||
All matches between both players
Danilovic O.
1
50%
Niemeier J.
1
50%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
MadridMadrid QR32 |
23/04/2024 |
Danilovic O. Niemeier J. 23/04/2024
|
6
6
4
4
|
2 0
|
|
LyonLyon R32 |
30/01/2023 |
Danilovic O. Niemeier J. 30/01/2023
|
5
6
3
7
2
6
|
1 2
|
Danilovic O. performance on Clay
Win
49
63%
Lose
27
35%
Total matches: 78
Cancelled: 2
Niemeier J. performance on Clay
Win
34
50%
Lose
28
41%
Total matches: 68
Cancelled: 6
Last 6 matches Danilovic O.
Win
3
50%
Lose
3
50%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Roland GarrosRoland Ga.. WTA French Open - 1/16-finals |
Sabalenka A. Danilovic O. 30/05/2025
|
6
6
2
3
|
2 0
|
|
Roland GarrosRoland Ga.. WTA French Open - 1/32-finals |
Collins D. Danilovic O. 28/05/2025
|
4
6
4
6
3
6
|
1 2
|
|
Roland GarrosRoland Ga.. WTA French Open - 1/64-finals |
Danilovic O. Fernandez L. 25/05/2025
|
6
6
3
1
|
2 0
|
|
Rome Italian OpenRome Ital.. R64 |
Danilovic O. Zheng Q. 09/05/2025
|
1
4
6
6
|
0 2
|
|
Rome Italian OpenRome Ital.. R128 |
Siniakova K. Danilovic O. 07/05/2025
|
6
4
4
3
6
6
|
1 2
|
|
MadridMadrid R64 |
Alexandrova E. Danilovic O. 25/04/2025
|
6
6
3
4
|
2 0
|
Last 6 matches Niemeier J.
Win
2
33%
Lose
4
67%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Rome Italian OpenRome Ital.. R32 |
Paolini J. Niemeier J. 10/05/2025
|
6
6
4
3
|
2 0
|
|
Rome Italian OpenRome Ital.. QR32 |
Niemeier J. Ruzic A. 06/05/2025
|
3
3
6
6
|
0 2
|
|
MadridMadrid R64 |
Uchijima M. Niemeier J. 25/04/2025
|
4
6
6
6
3
4
|
2 1
|
|
MadridMadrid QR64 |
Niemeier J. Zakharova A. 21/04/2025
|
6
7
3
5
|
2 0
|
|
StuttgartStuttgart R16 |
Niemeier J. Paolini J. 17/04/2025
|
1
5
6
7
|
0 2
|
|
StuttgartStuttgart R32 |
Niemeier J. Siegemund L. 15/04/2025
|
4
6
6
6
3
4
|
2 1
|