Hontama M.JPN () vs Liu C.CHN ()
predictions and statistics
05/03/2024 20:35
Indian Wells, surface: Hard
| Round | Match | Prob. in % | Tip | Pred. Sets |
Games | FT | |
|---|---|---|---|---|---|---|---|
| QR32 |
Hontama M.(JPN) Liu C.(CHN) 05/03/2024 20:35
|
57 | 43 | 1 | 2 0 |
6
5
6
1
7
3
|
2 1
|
All matches between both players
Hontama M.
1
100%
Liu C.
0
0%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
Indian WellsIndian We.. QR32 |
05/03/2024 |
Hontama M. Liu C. 05/03/2024
|
6
5
6
1
7
3
|
2 1
|
Hontama M. performance on Hard
Win
31
44%
Lose
34
48%
Total matches: 71
Cancelled: 6
Liu C. performance on Hard
Win
51
43%
Lose
56
47%
Total matches: 119
Cancelled: 12
Last 6 matches Hontama M.
Win
3
50%
Lose
3
50%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
PraguePrague WTA Livesport Prague Open - 1/16-finals |
Hontama M. Parks A. 21/07/2025
|
4
2
6
6
|
0 2
|
|
PraguePrague WTA Livesport Prague Open - Final - Qualification |
Martincova T. Hontama M. 20/07/2025
|
4
0
6
6
|
0 2
|
|
PraguePrague WTA Livesport Prague Open - Semi-finals - Qualific |
Hindova D. Hontama M. 19/07/2025
|
1
0
6
6
|
0 2
|
|
Roland GarrosRoland Ga.. WTA French Open - Semi-finals - Qualification |
Hontama M. Jones F. 22/05/2025
|
6
3
4
2
6
6
|
1 2
|
|
Roland GarrosRoland Ga.. WTA French Open - Quarter-finals - Qualification |
Pridankina E. Hontama M. 20/05/2025
|
2
5
6
7
|
0 2
|
|
Australian OpenAustralia.. QR128 |
Hontama M. Sharma A. 07/01/2025
|
6
3
4
3
6
6
|
1 2
|
Last 6 matches Liu C.
Win
3
50%
Lose
3
50%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
CharlestonCharleston QR16 |
Caty McNally Liu C. 30/03/2025
|
6
6
1
3
|
2 0
|
|
MiamiMiami R128 |
Liu C. Fruhvirtova L. 18/03/2025
|
5
6
3
7
4
6
|
1 2
|
|
MiamiMiami QR32 |
Liu C. Sorribes Tormo S. 17/03/2025
|
7
6
6
3
|
2 0
|
|
MiamiMiami QR64 |
Dolehide C. Liu C. 16/03/2025
|
6
6
2
2
7
6
|
1 2
|
|
Indian WellsIndian We.. R128 |
Liu C. Kudermetova P. 06/03/2025
|
4
2
6
6
|
0 2
|
|
Indian WellsIndian We.. QR32 |
Sorribes Tormo S. Liu C. 04/03/2025
|
4
3
6
6
|
0 2
|