Jabeur O.TUN (97) vs Zhang S.CHN (35)
predictions and statistics
31/12/2018 03:10
Shenzhen, surface: Hard
| Round | Match | Prob. in % | Tip | Pred. Sets |
Games | FT | |
|---|---|---|---|---|---|---|---|
| R32 |
Jabeur O.(TUN) Zhang S.(CHN) 31/12/2018 03:10
|
47 | 53 | 2 | 1 2 |
6
6
2
3
|
2 0
|
All matches between both players
Jabeur O.
1
100%
Zhang S.
0
0%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
ShenzhenShenzhen R32 |
31/12/2018 |
Jabeur O. Zhang S. 31/12/2018
|
6
6
2
3
|
2 0
|
Jabeur O. performance on Hard
Win
111
50%
Lose
91
41%
Total matches: 221
Cancelled: 19
Zhang S. performance on Hard
Win
166
45%
Lose
169
46%
Total matches: 371
Cancelled: 36
Last 6 matches Jabeur O.
Win
2
33%
Lose
4
67%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
WimbledonWimbledon WTA Wimbledon - 1/64-finals |
Tomova V. Jabeur O. 30/06/2025
|
8
2
7
0
|
Ret |
|
EastbourneEastbourne WTA Eastbourne - 1/16-finals |
Joint M. Jabeur O. 23/06/2025
|
7
6
5
2
|
2 0
|
|
BerlinBerlin WTA Berlin - Quarter-finals |
Jabeur O. Vondrousova M. 20/06/2025
|
4
1
6
6
|
0 2
|
|
BerlinBerlin WTA Berlin - 1/8-finals |
Paolini J. Jabeur O. 18/06/2025
|
1
3
6
6
|
0 2
|
|
BerlinBerlin WTA Berlin - 1/16-finals |
Dolehide C. Jabeur O. 16/06/2025
|
7
1
8
6
|
0 2
|
|
BerlinBerlin WTA Berlin - Final - Qualification |
Wang Xin. Jabeur O. 15/06/2025
|
6
3
6
1
6
0
|
2 1
|
Last 6 matches Zhang S.
Win
3
50%
Lose
3
50%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Hong KongHong Kong WTA Hong Kong - 1/8-finals |
Kalinskaya A. Zhang S. 30/10/2025
|
6
6
1
1
|
2 0
|
|
Hong KongHong Kong WTA Hong Kong - 1/16-finals |
Erjavec V. Zhang S. 28/10/2025
|
2
2
6
6
|
0 2
|
|
BeijingBeijing WTA Beijing - 1/16-finals |
Zhang S. Anisimova A. 28/09/2025
|
6
0
7
6
|
0 2
|
|
BeijingBeijing WTA Beijing - 1/32-finals |
Wang Xin. Zhang S. 26/09/2025
|
4
2
6
6
|
0 2
|
|
BeijingBeijing WTA Beijing - 1/64-finals |
Zakharova A. Zhang S. 24/09/2025
|
6
1
4
3
6
6
|
1 2
|
|
US OpenUS Open WTA US Open - 1/64-finals |
Zhang S. Bencic B. 24/08/2025
|
3
3
6
6
|
0 2
|