Kalinskaya A.RUS (70) vs Jabeur O.TUN (5)
predictions and statistics

07/04/2023 18:00
Charleston, surface: Clay
Round | Match | Prob. in % | Tip | Pred. Sets |
Games | FT | |
---|---|---|---|---|---|---|---|
QF |
Kalinskaya A.(RUS) Jabeur O.(TUN) 07/04/2023 18:00
|
31 | 69 | 2 | 0 2 |
0
1
6
4
|
Ret |
All matches between both players
Kalinskaya A.
0
0%
Jabeur O.
Cancelled: 1
1
50%
Cancelled: 1
TournamentTour. | Date | Match | Games | FT |
---|---|---|---|---|
CharlestonCharleston QF |
07/04/2023 |
Kalinskaya A. Jabeur O. 07/04/2023
|
0
1
6
4
|
Ret |
Indian WellsIndian We.. R16 |
13/10/2021 |
Jabeur O. Kalinskaya A. 13/10/2021
|
6
6
2
2
|
2 0
|
Kalinskaya A. performance on Clay
Win
25
40%
Lose
29
47%
Total matches: 62
Cancelled: 8
Jabeur O. performance on Clay
Win
60
65%
Lose
28
30%
Total matches: 92
Cancelled: 4
Last 6 matches Kalinskaya A.
Win
2
33%
Lose
4
67%
Tour. | Match | Games | FT |
---|---|---|---|
Roland GarrosRoland Ga.. WTA French Open - 1/64-finals |
Kalinskaya A. Bouzkova M. 27/05/2025
|
4
5
6
7
|
0 2
|
StrasbourgStrasbourg WTA Strasbourg - 1/8-finals |
Pegula J. Kalinskaya A. 21/05/2025
|
6
4
2
4
6
6
|
1 2
|
StrasbourgStrasbourg WTA Strasbourg - 1/16-finals |
Kalinskaya A. Dolehide C. 19/05/2025
|
6
4
6
2
6
3
|
2 1
|
Rome Italian OpenRome Ital.. R64 |
Alexandrova E. Kalinskaya A. 08/05/2025
|
6
6
2
3
|
2 0
|
Rome Italian OpenRome Ital.. R128 |
Dolehide C. Kalinskaya A. 07/05/2025
|
7
5
6
6
7
2
|
2 1
|
MadridMadrid R32 |
Keys M. Kalinskaya A. 26/04/2025
|
7
7
5
6
|
2 0
|
Last 6 matches Jabeur O.
Win
2
33%
Lose
4
67%
Tour. | Match | Games | FT |
---|---|---|---|
Roland GarrosRoland Ga.. WTA French Open - 1/64-finals |
Frech M. Jabeur O. 27/05/2025
|
8
6
6
0
|
2 0
|
MiamiMiami R64 |
Jabeur O. Siniakova K. 20/03/2025
|
6
7
4
6
|
2 0
|
Indian WellsIndian We.. R64 |
Jabeur O. Yastremska D. 07/03/2025
|
3
1
6
6
|
0 2
|
DubaiDubai R64 |
Jabeur O. Stearns P. 17/02/2025
|
6
4
7
6
|
0 2
|
DohaDoha QF |
Jabeur O. Ostapenko J. 13/02/2025
|
2
2
6
6
|
0 2
|
DohaDoha R16 |
Jabeur O. Kenin S. 12/02/2025
|
6
6
3
4
|
2 0
|