Kerber A.GER (212) vs Zheng Q.CHN ()
predictions and statistics
31/07/2024 13:05
Paris Olympics, surface: Clay
| Round | Match | Prob. in % | Tip | Pred. Sets |
Games | FT | |
|---|---|---|---|---|---|---|---|
| QF |
Kerber A.(GER) Zheng Q.(CHN) 31/07/2024 13:05
|
57 | 43 | 1 | 2 1 |
7
4
6
6
6
7
|
1 2
|
All matches between both players
Kerber A.
1
50%
Zheng Q.
1
50%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
Paris OlympicsParis Oly.. QF |
31/07/2024 |
Kerber A. Zheng Q. 31/07/2024
|
7
4
6
6
6
7
|
1 2
|
|
Indian WellsIndian We.. R64 |
12/03/2022 |
Zheng Q. Kerber A. 12/03/2022
|
2
7
4
6
5
6
|
1 2
|
Kerber A. performance on Clay
Win
105
59%
Lose
63
36%
Total matches: 177
Cancelled: 8
Zheng Q. performance on Clay
Win
50
68%
Lose
16
22%
Total matches: 73
Cancelled: 7
Last 6 matches Kerber A.
Win
3
50%
Lose
3
50%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Paris OlympicsParis Oly.. QF |
Kerber A. Zheng Q. 31/07/2024
|
7
4
6
6
6
7
|
1 2
|
|
Paris OlympicsParis Oly.. R16 |
Kerber A. Fernandez L. A. 30/07/2024
|
6
6
4
3
|
2 0
|
|
Paris OlympicsParis Oly.. R32 |
Cristian J. Kerber A. 29/07/2024
|
4
6
4
6
3
6
|
1 2
|
|
Paris OlympicsParis Oly.. R64 |
Osaka N. Kerber A. 27/07/2024
|
5
3
7
6
|
0 2
|
|
Bad HomburgBad Hombu.. R32 |
Kerber A. Shnaider D. 24/06/2024
|
5
3
7
6
|
0 2
|
|
BerlinBerlin R32 |
Noskova L. Kerber A. 18/06/2024
|
7
2
6
6
6
4
|
2 1
|
Last 6 matches Zheng Q.
Win
3
50%
Lose
2
33%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Indian WellsIndian We.. WTA Indian Wells - 1/32-finals |
Ruzic A. Zheng Q. 08/03/2026
|
6
7
4
5
|
2 0
|
|
DohaDoha WTA Doha - 1/8-finals |
Zheng Q. Rybakina E. 11/02/2026
|
6
2
5
4
6
7
|
1 2
|
|
DohaDoha WTA Doha - 1/16-finals |
Parks A. Zheng Q. 10/02/2026
|
6
6
2
8
3
6
|
1 2
|
|
DohaDoha WTA Doha - 1/32-finals |
Zheng Q. Kenin S. 09/02/2026
|
4
6
6
6
1
2
|
2 1
|
|
BeijingBeijing WTA Beijing - 1/16-finals |
Noskova L. Zheng Q. 29/09/2025
|
6
3
3
4
6
0
|
Ret |
|
BeijingBeijing WTA Beijing - 1/32-finals |
Arango E. Zheng Q. 27/09/2025
|
3
2
6
6
|
0 2
|