Niemeier J.GER () vs Kenin S.USA ()
predictions and statistics
06/02/2023 18:55
Linz, surface: Hard
| Round | Match | Prob. in % | Tip | Games | FT | |
|---|---|---|---|---|---|---|
| R32 |
Niemeier J.(GER) Kenin S.(USA) 06/02/2023 18:55
|
2
6
6
6
3
4
|
2 1
|
|||
All matches between both players
Niemeier J.
2
100%
Kenin S.
0
0%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
LinzLinz R32 |
06/02/2023 |
Niemeier J. Kenin S. 06/02/2023
|
2
6
6
6
3
4
|
2 1
|
|
US OpenUS Open R128 |
31/08/2022 |
Kenin S. Niemeier J. 31/08/2022
|
6
4
7
6
|
0 2
|
Niemeier J. performance on Hard
Win
26
42%
Lose
33
53%
Total matches: 62
Cancelled: 3
Kenin S. performance on Hard
Win
102
49%
Lose
89
43%
Total matches: 208
Cancelled: 17
Last 6 matches Niemeier J.
Win
1
17%
Lose
5
83%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
HamburgHamburg WTA Hamburg - 1/16-finals |
Niemeier J. Yastremska D. 16/07/2025
|
4
3
6
6
|
0 2
|
|
Rome Italian OpenRome Ital.. R32 |
Paolini J. Niemeier J. 10/05/2025
|
6
6
4
3
|
2 0
|
|
Rome Italian OpenRome Ital.. QR32 |
Niemeier J. Ruzic A. 06/05/2025
|
3
3
6
6
|
0 2
|
|
MadridMadrid R64 |
Uchijima M. Niemeier J. 25/04/2025
|
4
6
6
6
3
4
|
2 1
|
|
MadridMadrid QR64 |
Niemeier J. Zakharova A. 21/04/2025
|
6
7
3
5
|
2 0
|
|
StuttgartStuttgart R16 |
Niemeier J. Paolini J. 17/04/2025
|
1
5
6
7
|
0 2
|
Last 6 matches Kenin S.
Win
2
33%
Lose
4
67%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
CincinnatiCincinnati WTA Cincinnati - 1/32-finals |
Kenin S. Gracheva V. 10/08/2025
|
8
3
3
7
6
6
|
1 2
|
|
MontrealMontreal WTA Montreal - 1/32-finals |
Kenin S. Mboko V. 30/07/2025
|
2
3
6
6
|
0 2
|
|
WashingtonWashington WTA Washington - 1/8-finals |
Townsend T. Kenin S. 24/07/2025
|
6
6
3
0
|
2 0
|
|
WashingtonWashington WTA Washington - 1/16-finals |
Baptiste H. Kenin S. 22/07/2025
|
3
6
6
8
|
0 2
|
|
WimbledonWimbledon WTA Wimbledon - 1/32-finals |
Kenin S. Maneiro J. 03/07/2025
|
1
6
6
8
|
0 2
|
|
WimbledonWimbledon WTA Wimbledon - 1/64-finals |
Kenin S. Townsend T. 01/07/2025
|
8
6
7
2
|
2 0
|