Niemeier J.GER (92) vs Kostyuk M.UKR (18)
predictions and statistics
15/01/2025 09:15
Australian Open, surface: Hard
| Round | Match | Prob. in % | Tip | Pred. Sets |
Games | FT | |
|---|---|---|---|---|---|---|---|
| R64 |
Niemeier J.(GER) Kostyuk M.(UKR) 15/01/2025 09:15
|
38 | 62 | 2 | 0 2 |
3
0
6
6
|
0 2
|
All matches between both players
Niemeier J.
0
0%
Kostyuk M.
1
100%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
Australian OpenAustralia.. R64 |
15/01/2025 |
Niemeier J. Kostyuk M. 15/01/2025
|
3
0
6
6
|
0 2
|
Niemeier J. performance on Hard
Win
26
42%
Lose
33
53%
Total matches: 62
Cancelled: 3
Kostyuk M. performance on Hard
Win
88
56%
Lose
60
38%
Total matches: 157
Cancelled: 9
Last 6 matches Niemeier J.
Win
1
17%
Lose
5
83%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
HamburgHamburg WTA Hamburg - 1/16-finals |
Niemeier J. Yastremska D. 16/07/2025
|
4
3
6
6
|
0 2
|
|
Rome Italian OpenRome Ital.. R32 |
Paolini J. Niemeier J. 10/05/2025
|
6
6
4
3
|
2 0
|
|
Rome Italian OpenRome Ital.. QR32 |
Niemeier J. Ruzic A. 06/05/2025
|
3
3
6
6
|
0 2
|
|
MadridMadrid R64 |
Uchijima M. Niemeier J. 25/04/2025
|
4
6
6
6
3
4
|
2 1
|
|
MadridMadrid QR64 |
Niemeier J. Zakharova A. 21/04/2025
|
6
7
3
5
|
2 0
|
|
StuttgartStuttgart R16 |
Niemeier J. Paolini J. 17/04/2025
|
1
5
6
7
|
0 2
|
Last 6 matches Kostyuk M.
Win
1
17%
Lose
5
83%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
MontrealMontreal WTA Montreal - 1/32-finals |
Kostyuk M. Vondrousova M. 29/07/2025
|
2
6
6
6
3
2
|
2 1
|
|
WashingtonWashington WTA Washington - 1/16-finals |
Kostyuk M. Raducanu E. 22/07/2025
|
6
4
8
6
|
0 2
|
|
WimbledonWimbledon WTA Wimbledon - 1/64-finals |
Erjavec V. Kostyuk M. 01/07/2025
|
3
6
6
6
3
4
|
2 1
|
|
Bad HomburgBad Hombu.. WTA Bad Homburg - 1/16-finals |
Kostyuk M. Navarro E. 22/06/2025
|
2
5
6
7
|
0 2
|
|
BerlinBerlin WTA Berlin - 1/16-finals |
Kostyuk M. Navarro E. 16/06/2025
|
2
3
6
6
|
0 2
|
|
Roland GarrosRoland Ga.. WTA French Open - 1/64-finals |
Kostyuk M. Bejlek S. 25/05/2025
|
3
1
6
6
|
0 2
|