Zheng Q.CHN () vs Avanesyan E.RUS ()
predictions and statistics
01/06/2024 10:05
Roland Garros, surface: Clay
| Round | Match | Prob. in % | Tip | Pred. Sets |
Games | FT | |
|---|---|---|---|---|---|---|---|
| R32 |
Zheng Q.(CHN) Avanesyan E.(RUS) 01/06/2024 10:05
|
58 | 42 | 1 | 2 0 |
6
3
6
3
6
7
|
1 2
|
All matches between both players
Zheng Q.
0
0%
Avanesyan E.
1
100%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
Roland GarrosRoland Ga.. R32 |
01/06/2024 |
Zheng Q. Avanesyan E. 01/06/2024
|
6
3
6
3
6
7
|
1 2
|
Zheng Q. performance on Clay
Win
50
68%
Lose
16
22%
Total matches: 73
Cancelled: 7
Avanesyan E. performance on Clay
Win
28
50%
Lose
24
43%
Total matches: 56
Cancelled: 4
Last 6 matches Zheng Q.
Win
3
50%
Lose
2
33%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Indian WellsIndian We.. WTA Indian Wells - 1/32-finals |
Ruzic A. Zheng Q. 08/03/2026
|
6
7
4
5
|
2 0
|
|
DohaDoha WTA Doha - 1/8-finals |
Zheng Q. Rybakina E. 11/02/2026
|
6
2
5
4
6
7
|
1 2
|
|
DohaDoha WTA Doha - 1/16-finals |
Parks A. Zheng Q. 10/02/2026
|
6
6
2
8
3
6
|
1 2
|
|
DohaDoha WTA Doha - 1/32-finals |
Zheng Q. Kenin S. 09/02/2026
|
4
6
6
6
1
2
|
2 1
|
|
BeijingBeijing WTA Beijing - 1/16-finals |
Noskova L. Zheng Q. 29/09/2025
|
6
3
3
4
6
0
|
Ret |
|
BeijingBeijing WTA Beijing - 1/32-finals |
Arango E. Zheng Q. 27/09/2025
|
3
2
6
6
|
0 2
|
Last 6 matches Avanesyan E.
Win
2
33%
Lose
4
67%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
MéridaMérida WTA Merida - Final - Qualification |
Lepchenko V. Avanesyan E. 22/02/2026
|
6
2
6
4
6
3
|
2 1
|
|
OstravaOstrava WTA Ostrava - 1/8-finals |
Parks A. Avanesyan E. 03/02/2026
|
6
6
4
2
|
2 0
|
|
OstravaOstrava WTA Ostrava - 1/16-finals |
Avanesyan E. Uchijima M. 01/02/2026
|
6
2
6
3
6
3
|
2 1
|
|
US OpenUS Open WTA US Open - 1/64-finals |
Zakharova A. Avanesyan E. 26/08/2025
|
6
6
3
4
|
2 0
|
|
IasiIasi WTA Iasi - 1/8-finals |
Avanesyan E. Carle M. 17/07/2025
|
6
2
8
6
|
0 2
|
|
IasiIasi WTA Iasi - 1/16-finals |
Avanesyan E. Prisacariu A. 15/07/2025
|
6
6
3
3
|
2 0
|