Azarenka V.BLR () vs Noskova L.CZE ()
predictions and statistics
24/06/2024 10:00
Bad Homburg, surface: Grass
| Round | Match | Prob. in % | Tip | Games | FT | |
|---|---|---|---|---|---|---|
| R32 |
Azarenka V.(BLR) Noskova L.(CZE) 24/06/2024 10:00
|
1 | ||||
All matches between both players
Azarenka V.
0
0%
Noskova L.
0
0%
| TournamentTour. | Date | Match | Games | FT |
|---|
Azarenka V. performance on Grass
Win
63
64%
Lose
29
30%
Total matches: 98
Cancelled: 5
Noskova L. performance on Grass
Win
11
50%
Lose
8
36%
Total matches: 22
Cancelled: 3
Last 6 matches Azarenka V.
Win
3
50%
Lose
3
50%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
WimbledonWimbledon WTA Wimbledon - 1/64-finals |
Azarenka V. Zakharova A. 01/07/2025
|
2
6
1
6
2
6
|
1 2
|
|
Bad HomburgBad Hombu.. WTA Bad Homburg - 1/8-finals |
Azarenka V. Swiatek I. 24/06/2025
|
4
4
6
6
|
0 2
|
|
Bad HomburgBad Hombu.. WTA Bad Homburg - 1/16-finals |
Azarenka V. Siegemund L. 23/06/2025
|
6
6
2
2
|
2 0
|
|
Bad HomburgBad Hombu.. WTA Bad Homburg - Final - Qualification |
Kudermetova V. Azarenka V. 22/06/2025
|
8
3
4
6
6
6
|
1 2
|
|
Roland GarrosRoland Ga.. WTA French Open - 1/32-finals |
Azarenka V. Kenin S. 29/05/2025
|
7
4
8
6
|
0 2
|
|
Roland GarrosRoland Ga.. WTA French Open - 1/64-finals |
Wickmayer Y. Azarenka V. 27/05/2025
|
0
0
6
6
|
0 2
|
Last 6 matches Noskova L.
Win
4
67%
Lose
2
33%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
WimbledonWimbledon WTA Wimbledon - 1/8-finals |
Noskova L. Anisimova A. 06/07/2025
|
2
7
4
6
5
6
|
1 2
|
|
WimbledonWimbledon WTA Wimbledon - 1/16-finals |
Rakhimova Noskova L. 04/07/2025
|
7
5
8
7
|
0 2
|
|
WimbledonWimbledon WTA Wimbledon - 1/32-finals |
Lys E. Noskova L. 02/07/2025
|
2
6
3
6
2
6
|
1 2
|
|
WimbledonWimbledon WTA Wimbledon - 1/64-finals |
Pera B. Noskova L. 30/06/2025
|
2
4
6
6
|
0 2
|
|
Bad HomburgBad Hombu.. WTA Bad Homburg - Semi-finals |
Pegula J. Noskova L. 27/06/2025
|
6
7
6
8
5
1
|
2 1
|
|
Bad HomburgBad Hombu.. WTA Bad Homburg - Quarter-finals |
Andreeva M. Noskova L. 26/06/2025
|
3
3
6
6
|
0 2
|