Bucsa C.MDA (86) vs Andreeva E.RUS ()
predictions and statistics
06/03/2023 20:45
Indian Wells, surface: Hard
| Round | Match | Prob. in % | Tip | Pred. Sets |
Games | FT | |
|---|---|---|---|---|---|---|---|
| QR64 |
Bucsa C.(MDA) Andreeva E.(RUS) 06/03/2023 20:45
|
57 | 43 | 1 | 2 0 |
6
7
3
5
|
2 0
|
All matches between both players
Bucsa C.
1
100%
Andreeva E.
0
0%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
Indian WellsIndian We.. QR64 |
06/03/2023 |
Bucsa C. Andreeva E. 06/03/2023
|
6
7
3
5
|
2 0
|
Bucsa C. performance on Hard
Win
82
53%
Lose
62
40%
Total matches: 156
Cancelled: 12
Andreeva E. performance on Hard
Win
33
46%
Lose
31
43%
Total matches: 72
Cancelled: 8
Last 6 matches Bucsa C.
Win
4
67%
Lose
2
33%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Hong KongHong Kong WTA Hong Kong - Final |
Bucsa C. Mboko V. 02/11/2025
|
5
7
2
7
7
6
|
1 2
|
|
Hong KongHong Kong WTA Hong Kong - Semi-finals |
Bucsa C. Joint M. 01/11/2025
|
6
6
3
1
|
2 0
|
|
Hong KongHong Kong WTA Hong Kong - 1/8-finals |
Bucsa C. Arango E. 29/10/2025
|
6
6
2
4
|
2 0
|
|
Hong KongHong Kong WTA Hong Kong - 1/16-finals |
Bucsa C. Ma Y. 27/10/2025
|
6
6
1
2
|
2 0
|
|
TokyoTokyo WTA Tokyo - 1/16-finals |
Bucsa C. Kessler M. 20/10/2025
|
6
5
3
3
7
6
|
1 2
|
|
TokyoTokyo WTA Tokyo - Final - Qualification |
Galfi D. Bucsa C. 19/10/2025
|
3
6
6
8
|
0 2
|
Last 6 matches Andreeva E.
Win
0
0%
Lose
6
100%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
WimbledonWimbledon WTA Wimbledon - Quarter-finals - Qualification |
Andreeva E. Janicijevic S. 24/06/2025
|
4
6
6
8
|
0 2
|
|
BerlinBerlin WTA Berlin - Semi-finals - Qualification |
Kenin S. Andreeva E. 14/06/2025
|
6
6
4
0
|
2 0
|
|
Roland GarrosRoland Ga.. WTA French Open - 1/64-finals |
Kartal S. Andreeva E. 27/05/2025
|
6
6
0
2
|
2 0
|
|
MadridMadrid QR64 |
Stefanini L. Andreeva E. 21/04/2025
|
7
6
5
4
|
2 0
|
|
StuttgartStuttgart R32 |
Andreeva M. Andreeva E. 16/04/2025
|
6
1
2
0
|
1 0
|
|
StuttgartStuttgart QQF |
Andreeva E. Sasnovich A. 13/04/2025
|
1
4
6
6
|
0 2
|