Kessler M.USA () vs Kalinina A.UKR (68)
predictions and statistics
01/04/2025 21:00
Charleston, surface: Clay
| Round | Match | Prob. in % | Tip | Pred. Sets |
Games | FT | |
|---|---|---|---|---|---|---|---|
| R64 |
Kessler M.(USA) Kalinina A.(UKR) 01/04/2025 21:00
|
45 | 55 | 2 | 0 2 |
7
5
6
5
7
4
|
2 1
|
All matches between both players
Kessler M.
1
100%
Kalinina A.
0
0%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
CharlestonCharleston R64 |
01/04/2025 |
Kessler M. Kalinina A. 01/04/2025
|
7
5
6
5
7
4
|
2 1
|
Kessler M. performance on Clay
Win
5
26%
Lose
12
63%
Total matches: 19
Cancelled: 2
Kalinina A. performance on Clay
Win
44
49%
Lose
30
34%
Total matches: 89
Cancelled: 15
Last 6 matches Kessler M.
Win
3
50%
Lose
3
50%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Queen's ClubQueen's C.. |
Zheng Q. Kessler M. 12/06/2025
|
6
4
7
3
6
5
|
2 1
|
|
Queen's ClubQueen's C.. |
Jones F. Kessler M. 10/06/2025
|
2
4
6
6
|
0 2
|
|
Roland GarrosRoland Ga.. WTA French Open - 1/64-finals |
Ruse G. Kessler M. 26/05/2025
|
7
8
5
6
|
2 0
|
|
StrasbourgStrasbourg WTA Strasbourg - 1/16-finals |
Kessler M. Krueger A. 19/05/2025
|
4
5
6
7
|
0 2
|
|
StrasbourgStrasbourg WTA Strasbourg - Final - Qualification |
Kessler M. Zarazua R. 18/05/2025
|
8
6
6
3
|
2 0
|
|
StrasbourgStrasbourg WTA Strasbourg - Semi-finals - Qualification |
Kessler M. Burrage J. 17/05/2025
|
6
5
6
4
7
2
|
2 1
|
Last 6 matches Kalinina A.
Win
3
50%
Lose
3
50%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Roland GarrosRoland Ga.. WTA French Open - 1/32-finals |
Kalinina A. Boisson L. 29/05/2025
|
1
2
6
6
|
0 2
|
|
Roland GarrosRoland Ga.. WTA French Open - 1/64-finals |
Avanesyan E. Kalinina A. 27/05/2025
|
1
2
6
6
|
0 2
|
|
Rome Italian OpenRome Ital.. R128 |
Kalinina A. Sevastova A. 06/05/2025
|
6
6
3
4
|
2 0
|
|
MadridMadrid R64 |
Keys M. Kalinina A. 24/04/2025
|
6
6
4
3
|
2 0
|
|
MadridMadrid R128 |
Osaka N. Kalinina A. 22/04/2025
|
4
6
4
6
2
6
|
1 2
|
|
RouenRouen R16 |
Svitolina E. Kalinina A. 17/04/2025
|
6
6
4
0
|
2 0
|