Kessler M.USA (42) vs Zhu L.CHN (309)
predictions and statistics
19/06/2025 10:00
Aegon Open Nottingham, surface: Clay
| Round | Match | Prob. in % | Tip | Pred. Sets |
Games | FT | |
|---|---|---|---|---|---|---|---|
| WTA Nottingham - 1/8-finals |
Kessler M.(USA) Zhu L.(CHN) 19/06/2025 10:00
|
70 | 30 | 1 | 2 1 |
||
All matches between both players
Kessler M.
1
100%
Zhu L.
0
0%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
Charleston 2Charlesto.. R32 |
12/03/2024 |
Zhu L. Kessler M. 12/03/2024
|
6
4
5
3
6
7
|
1 2
|
Kessler M. performance on Clay
Win
5
26%
Lose
12
63%
Total matches: 19
Cancelled: 2
Zhu L. performance on Clay
Win
11
34%
Lose
20
63%
Total matches: 32
Cancelled: 1
Last 6 matches Kessler M.
Win
3
50%
Lose
3
50%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Aegon Open NottinghamAegon Ope.. WTA Nottingham - 1/16-finals |
Haddad M. B. Kessler M. 17/06/2025
|
5
8
5
7
6
7
|
1 2
|
|
Queen's ClubQueen's C.. |
Zheng Q. Kessler M. 12/06/2025
|
6
4
7
3
6
5
|
2 1
|
|
Queen's ClubQueen's C.. |
Jones F. Kessler M. 10/06/2025
|
2
4
6
6
|
0 2
|
|
Roland GarrosRoland Ga.. WTA French Open - 1/64-finals |
Ruse G. Kessler M. 26/05/2025
|
7
8
5
6
|
2 0
|
|
StrasbourgStrasbourg WTA Strasbourg - 1/16-finals |
Kessler M. Krueger A. 19/05/2025
|
4
5
6
7
|
0 2
|
|
StrasbourgStrasbourg WTA Strasbourg - Final - Qualification |
Kessler M. Zarazua R. 18/05/2025
|
8
6
6
3
|
2 0
|
Last 6 matches Zhu L.
Win
2
33%
Lose
4
67%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Aegon Open NottinghamAegon Ope.. WTA Nottingham - 1/16-finals |
Zhu L. Sasnovich A. 16/06/2025
|
6
6
4
1
|
2 0
|
|
Australian OpenAustralia.. QR128 |
Zhu L. Janicijevic S. 06/01/2025
|
3
6
2
6
1
6
|
1 2
|
|
BirminghamBirmingham R16 |
Tomljanovic A. Zhu L. 19/06/2024
|
6
6
6
7
1
4
|
2 1
|
|
BirminghamBirmingham R32 |
Zhu L. Cirstea S. 17/06/2024
|
7
6
6
2
|
2 0
|
|
Aegon Open NottinghamAegon Ope.. R32 |
Stefanini L. Zhu L. 10/06/2024
|
7
3
7
6
6
5
|
2 1
|
|
Roland GarrosRoland Ga.. R128 |
Zhu L. Avanesyan E. 28/05/2024
|
2
4
6
6
|
0 2
|